**Identification**: we have a group of N people with some known possible set of identifications, and we ask questions to determine what tribe each is from.**Information**: We have a group of N people with some known possible set of identifications, and we ask them questions to determine M bits of information (independent yes/no questions). We do not need to identify the tribe of each person. For concreteness, we will take the bits to be 1s or 0s (i.e. we want to find whether the bit is 1 or 0)

### A Brief Primer in some Information concepts

The fundamental unit of information is the bit. A single bit answers one yes/no question. If both answers are equally likely, the answer gives the most information, as otherwise you could guess the answer more easily. (In fact, the formula for the effective number of bits, if the chance of a "yes" answer is p, is given by: \(-p\log_2(p)-(1-p)\log_2(1-p) \approx 4p(1-p)\)). If there are \(2^N\) equally possible options, it takes N bits of information to narrow it down to one: in general, an additional bit halves the possibility space. If there are M possibilities, and \(2^{N-1}< M \leq 2^N\), then N bits of information are required. From a deterministic source--that is, a source with known, predictable behavior--one answer to one yes/no question yields at most 1 bit of information, and exactly one if both answers are equally probable. In general, if we discover M bits of information with N questions, if we only want a smaller number of bits, we will need fewer questions.

We will discuss some specific cases, describing some general methods of approaching the problem. We will forgo trivial cases, like asking a 1-bit question to someone of a known tribe, or identifying a person from an unknown tribe.

### Information: One Person of Unknown Tribe, One Bit

Clearly we must ask at least one question, but can we determine it in exactly one question? Indeed we can. Our goal is to formulate a question such that, regardless of whether the person is a liar or a truther, the answer will correspond to the truth. We thus construct the following table, and look for a question such which would produce the listed "real answers" (answers taking into account whether the teller is a liar or truther).

Bit Value |
Identity |
Given Answer |
Honest Answer |

1 | Truther | Yes | Yes |

1 | Liar | Yes | No |

0 | Truther | No | No |

0 | Liar | No | Yes |

Is one of the following true: the bit is 1 and you are a truther, the bit is 0 and you are a liar?Regardless of whether the person asked is a truther or liar, the answer will always be "yes" if the bit is 1 and "no" if it is 0. The question may be found to simplify to something more natural sounding, but the question as given is sufficient. Moreover, if we require N bits of information, we can achieve such in exactly N questions. This will be our general approach. We will make a table in which the given answer corresponds to the information we seek. We will then formulate a question such as to produce the desired answer. This can be done most easily by forming a disjunction of the answers producing an affirmative.

### Identification: One Person of Unknown Tribe, Unknown Language

In this case, the tribespeople have a language different than yours. They can understand your questions but reply in a way you can't understand. We will assume that you know the words for "yes" and "no" are "da" and "ja", but you don't know which corresponds to which. If you do not even know what the possible words for "yes" and "no" are, you can find this out with one additional question, merely by asking anything and then knowing that the response either means "yes" or "no". The question is then whether you can identify the tribe of the person, and in as few questions as possible. Given that we only seek one bit of information (the person is either a truther or a liar), we will attempt to do so with a single question. We will look for a question such that the response corresponds to the identity of the person. For concreteness, we will take "Da" to be indicative of a truther, "Ja" of a liar.

Identity |
Translation of "Da" |
Given Answer |
Translated Answer |
Honest Answer |

Truther | Yes | Da | Yes | Yes |

Truther | No | Da | No | No |

Liar | Yes | Ja | No | Yes |

Liar | No | Ja | Yes | No |

Does "Da" mean "yes"?A truther will always answer "Da", and a liar will always answer "Ja". Note that we cannot determine what "Da" actually means from this question, and this accords with information theory concepts. We can only get one bit of information from one question. If we wanted to identify what "Da" meant without knowing the identiy, by a similar method we would find that the following question achieves that:

Is one of the following true: "Da" means "yes" and you are a truther, "Da" means "no" and you are a liar?If the answer is "Da", "Da" means "yes".

### Information: One Person of Unknown Tribe, Unknown Language, One Bit

This case is much like the preceding one, except we require neither then meaning of "Da" nor the identity of the person. As we need only one bit of information, we require at least one question. We will show how to do it in exactly one question. As before, we construct a table, but this time with three independent variables: the value of the bit, the identity of the person, and the meaning of "Da".

Bit Value |
Identity |
Translation of "Da" |
Given Answer |
Translated Answer |
Honest Answer |

1 | Truther | Yes | Da | Yes | Yes |

1 | Truther | No | Da | No | No |

1 | Liar | Yes | Da | Yes | No |

1 | Liar | No | Da | No | Yes |

0 | Truther | Yes | Ja | No | No |

0 | Truther | No | Ja | Yes | Yes |

0 | Liar | Yes | Ja | No | Yes |

0 | Liar | No | Ja | Yes | No |

Is one of the following true: you are a truther and "Da" means "yes" and the bit is 1, you are a liar and "Da" means "no" and the bit is 1, you are a truther and "Da" means "no" and the bit is 0, you are a liar and "Da" means "yes" and the bit is 0 ?A simpler way would be to ask:

Is an odd number of the following true: the bit is 1, you are a truther, "Da" means "yes"?In general, we can see that we can always get exactly one bit of information from one question, given certain other constraints. Not knowing the language or the identity of the person asked are no hindrances to getting information. Also, if we have \(2^M\) people from potentially different tribes who speak the same unknown language, or even if we only know the potential words for "yes" and "no" for one of their languages, we can still identify all of them in exactly M questions just by asking the one person M questions.

### Identification: Truther, Liar, and Unhelpful in Unknown Order.

In this case, we have three people known to be some permutation of truther, liar and a third kind we call unhelpful. The unhelpful is a third type of tribesperson who answers so as to be maximally unhelpful. That is, he will answer so as to prevent you from getting information. The goal is to identify him regardless, as well as the other two. The first question is whether we can identify the three, and then, if it is possible, to do so in as few questions as we can. As there are 6 possible orderings, we will need 3 bits of information, corresponding to at least 3 questions. We must ask each person at least one question, as only asking 2 or fewer risks only asking the unhelpful, who provides no information. However, if we ask each of them one question, we only get two bits of information, as the unhelpful provides none. Thus we must ask at least 4 questions, with the 4th question being asked of one of the non-unhelpfuls.

In fact there is a way to do this. We ask a question which the truther and the liar will answer differently. We then take the odd one out among the three, who is guaranteed to be either a truther or a liar (in fact, the way he answers will decide which) and then ask him for one more bit of information to identify one of the others, which we have already described how to do. So, for instance, we can ask all three "Do you exist?" (or, if the language is unknown "Does 'Da' mean 'yes'?"). And then concoct a question to ask the odd one out to get the final requisite bit (left as an exercise for the reader). Thus we can achieve it in exactly 4 questions. In fact, for the first three questions, we only get 2/3 of a bit of information per answer, as, for each answer, we get 1 bit with 2/3 probability.